The **oxidation state** of P in **PO4** can be calculated as under. **PO4** has 3- charge on it.

Secondly, what is the oxidation state of an individual phosphorus atom in Po 3 3 −? The **oxidation state** of P in **PO33**– is **3**.

Then, how do you find the oxidation number of phosphorus?

Letting x be the **oxidation number of phosphorus**, 0= 3( 1) x 3(-2). x=**oxidation number of P**= 3. Hydrogen and oxygen have **oxidation numbers** of 1 and -2. The ion has a charge of -1, so the sum of the **oxidation numbers** must be -1.

What is the oxidation number for phosphorus in na2hpo3?

The **oxidation number** of the **phosphorus** is 3. We know that hydrogen ions have a 1 **oxidation number** and oxygen ions have a -2 **oxidation number**.