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What is the oxidation state of an individual phosphorus atom in po43 -?
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In the phosphate ion, the oxidation number of phosphorous is 5. The sum of the oxidation numbers in PO43-, a polyatomic ion, is -3, the charge of the ion. We assign -2 as the oxidation number of each O and x as the oxidation number of P and write the following equation: x 4(-2) = -3…. x = 5.
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The oxidation state of P in PO4 can be calculated as under. PO4 has 3- charge on it.
Secondly, what is the oxidation state of an individual phosphorus atom in Po 3 3 −? The oxidation state of P in PO33– is 3.
Then, how do you find the oxidation number of phosphorus?
Letting x be the oxidation number of phosphorus, 0= 3( 1) x 3(-2). x=oxidation number of P= 3. Hydrogen and oxygen have oxidation numbers of 1 and -2. The ion has a charge of -1, so the sum of the oxidation numbers must be -1.
What is the oxidation number for phosphorus in na2hpo3?
The oxidation number of the phosphorus is 3. We know that hydrogen ions have a 1 oxidation number and oxygen ions have a -2 oxidation number.
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